Quantum redactiones paginae "Numerus e" differant
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m bot mutat: uk:E (число) |
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Formulae calculandi:
:<math>e = \lim_{n\to\infty} (1+ \frac{1}{n})^n = \sum_{n=1}^\infty { \ \frac {1} {n!}}</math>
id est,
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