Quantum redactiones paginae "Superfluidum" differant

:<math>\frac{P'^2}{2M}-\frac{P^2}{2M}=-\frac{\vec P \cdot \vec p}{M}+\frac{p^2}{2M}</math>

Quo obtinemus

Identificando corporis velocitas <math>v=\frac{P}{M}</math>, <math>M \gg 1</math> inserendo, et solvendo, tunc

:<math>v \cos \theta = \frac{\epsilon}{p}+\frac{p}{2M} \approx \frac{\epsilon}{p}</math>,