Emendatio ex 10:23, 20 Septembris 2007 recensere Rafaelgarcia (disputatio \| conlationes) Magistratus 22 242 edits →‎Demonstratio ← Differentia superior		Emendatio ex 12:06, 20 Septembris 2007 recensere abrogare Rafaelgarcia (disputatio \| conlationes) Magistratus 22 242 edits →‎Demonstratio Differentia proxima →
Linea 14: :::<math> \frac{\delta S}{\delta x_\alpha} = 0</math>. EQua ~~quo~~ex aequatione Langrange ~~obtinuit~~deduxit aequationes Euler-Lagrange: :::<math>\frac{d~}{dt} \ \left( \, \frac{\partial L}{\partial \dot{x}_\alpha} \, \right) \ - \ \frac{\partial L}{\partial x_\alpha} \ = \ 0</math> Langrange ~~deinde~~ invenit has aequationes illi Newtonianae corrrespondere si solum si ''L = T - V'' ponamus, id est, si functio Lagrangiana ponatur aequalis differentiae inter energiam cineticam et energiam potentialem. Si singula particula [[Relativitas specialis\|arelativistica]] energia ''V'' potentiali in tribus dimensionibus habeamus, functio Langrangiana sua est :::<math>L(\vec{x}, \dot{\vec{x}}) \ = \ \frac{1}{2} \ m \ \dot{\vec{x}}^2 \ - \ V(\vec{x})</math>. Linea 29: :::<math>\frac{d~}{dt} \ \left( \, \frac{\partial L}{\partial \dot{x}_\alpha} \, \right) \ = \ m \, \ddot{x}_\alpha, </math> ut possemus aequationes Euler-Lagrange scribere: :::<math>m\ddot{\vec{x}}+\nabla V=0</math>.

Quantum redactiones paginae "Aequationes Lagrangi" differant