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Summarium
DescriptioHyperbolicAnimation.gif
English: Animated plot of the trigonometric (circular) and hyperbolic functions.
In red, curve of equation x² + y² = 1 (unit circle), and in blue, x² - y² = 1 (equilateral hyperbola), with the points (cos(θ),sin(θ)) and (1,tan(θ)) in red and (cosh(θ),sinh(θ)) and (1,tanh(θ)) in blue.
Français : Diagramme animé des fonctions trigonométriques usuelles et des fonctions hyperboliques
En rouge, la courbe d'équation x² + y² = 1 (le cercle unité), et en bleu celle d'équation, x² - y² = 1 (l'hyperbole équilaterale), avec les points points (cos(θ),sin(θ)) et (1,tan(θ)) représentés en rouge, ainsi que (cosh(θ),sinh(θ)) et (1,tanh(θ)) représenté en bleu.
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Sam Derbyshire from en.wikipedia.org, the copyright holder of this work, hereby publishes it under the following license:
Licet hoc documentum exscribere vel distribuere vel demutare sub GNU Liberarum Litterarum Licentiae conditionibus in editione 1.2 aut in ulla editione recentiori a Fundatione Liberarum Programmationis Partium publicata; praeterquam Sectiones Immutabiles et Verba Involucra Adversa et Aversa. Licentiae exemplar praesto est in sectione intitulata GNU Free Documentation License. Subject to disclaimers.http://www.gnu.org/copyleft/fdl.htmlGFDLGNU Free Documentation Licensetruetrue
Original upload log
The original description page was here. All following user names refer to en.wikipedia.
2006-11-10 22:28 Sam Derbyshire 489×443×7 (1142785 bytes) Animated plot of the trigonometric (circular) and hyperbolic functions. In red, curve of equation x² + y² = 1 (unit circle), and in blue, x² - y² = 1 (equilateral hyperbola), with the points (cos(θ),sin(θ)) and (1,tan(θ)) in red and (cosh(θ),sinh(
for red points,(1,tan∅)have the unlimited Y value; while (1,tanh∅)'s maximal y vlue is 1.That's what you see in this animated graph.
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{{BotMoveToCommons|en.wikipedia}} {{Information |Description={{en|Animated plot of the trigonometric (circular) and hyperbolic functions. In red, curve of equation x² + y² = 1 (unit circle), and in blue, x² - y² = 1 (equilateral hyperbola), w